Subjective Type

State Ampere's circuital law.

Solution

The line integral of the magnetic field around some closed loop is equal to the times the algebraic sum of the currents which pass through the loop.

SIMILAR QUESTIONS

Magnetism

A hollow tube is carrying an electric current along its length distributed uniformly over its surface. The magnetic field :

Magnetism

A steady electric current is flowing through a cylindrical conductor

Magnetism

A long straight wire of radius R carries a current distributed uniformly over its cross-section. The magnitude of the magnetic field is

Magnetism

In a coaxial, straight cable, the central conductor and the outer conductor carry equal currents in opposite directions. The magnetic field is zero :

Magnetism

Sometimes we show an idealised magnetic field which is uniform in a given region and falls to zero abruptly. One such field is represented in figure. Using Ampere's law over the path PQRS, show that such a field is not possible.

Magnetism

The coil of a dynamo is rotating in a magnetic field. The developed induced emf changes and the number of magnetic lines of force also changes. Which of the following conditions is correct?

Magnetism

A current of $$\dfrac{1}{(4\pi)}$$ ampere is flowing in a long straight conductor. The line integral of magnetic induction around a closed path enclosing the current-carrying conductor is

Magnetism

Figure shows an Amperian path $$ABCDA$$. Part $$ABC$$ is in verical plane $$PSTU$$ while part $$CDA$$ is in horizontal plane $$PQRS$$. Direction of circulation along the path is shown by an arrow near point $$B$$ and $$D$$. $$\oint { \vec { B } .d\vec { l } } $$ for this path according to Ampere's law will be :

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