State one way to decrease the moment of a given force about a given axis of rotation.
Moment of force= Force x Distance of force from axis of rotation.
To decrease the moment of a given force about a given axis of rotation,either decrease the force or decrease the perpendicular distance of force
from axis of rotation.
A slob is subjected to two force $$\overset{\rightarrow}{F_1}$$ and $$\overset{\rightarrow}{F_2}$$ of same magnitude $$F$$ as shown in the figure .Force $$\overset{\rightarrow}{F_2}$$ is in $$XY-$$ plane while force $$\overset{\rightarrow}{F_1}$$ acts along $$z-$$axis at the point $$(2\overset{\rightarrow}{i}+3\overset{\rightarrow}{j})$$. The moment of these forces about point O will be :
A uniform disc is acted by two equal forces of magnitude F. One of them, acts tangentially to the disc, while other one is acting at the central point of the disc. The friction between disc surface and ground surface is nF. If r be the radius of the disc, then the value of n would be? (in N)
The dimensions of torque are same as that of
Given $$\vec {F}$$ = (4$$\hat {i}$$ -10$$\hat {j}$$) and $$\vec {r}$$= (5$$\hat {i}$$-3$$\hat {j}$$). Then torque $$\tau$$ is
Moment of force= _____ $$ \times $$ distance of force from the point of turning.
In a door, handle is provided ______. from the hinges.
To obtain a given moment of force for turning a body, the force needed can be decreased by
Draw a diagram of the arrangement.
State two factors on which moment of force at a point depends?
Is the moment of force a scalar or a vector?