Nuclear Physics
The transition from the state $$n = 4$$ to $$n = 3$$ in a hydrogen like atom results in ultraviolet radiation. Infrared radiation will be obtained in the transition from
Taking the wavelength of first Balmer line in hydrogen spectrum ($$n=3$$ to $$n=2$$) as $$660nm$$, the wavelength of the 2nd Balmer line ($$n=4$$ to $$n=2$$) will be:
$$\cfrac { 1 }{ 660 } =R\left( \cfrac { 1 }{ { 2 }^{ 2 } } -\cfrac { 1 }{ { 3 }^{ 2 } } \right) =\cfrac { 5R }{ 36 } ....(1)\quad $$
$$\cfrac { 1 }{ \lambda } =R\left( \cfrac { 1 }{ { 2 }^{ 2 } } -\cfrac { 1 }{ { 4 }^{ 2 } } \right) =\cfrac { 3R }{ 16 } ....(2)\quad \quad $$
dividing (1) with (2)
$$\cfrac { \lambda }{ 660 } =\cfrac { 5\times 16 }{ 36\times 3 } $$
$$\lambda =\cfrac { 4400 }{ 9 } =488.88=488.9nm$$
The transition from the state $$n = 4$$ to $$n = 3$$ in a hydrogen like atom results in ultraviolet radiation. Infrared radiation will be obtained in the transition from
Hydrogen atom is excited from ground state to another state with principal quantum number equal to $$4$$. Then the number of spectral lines in the emission spectra will be.
The transition from the state $$n=3$$ to $$n=1$$ in a hydrogen like atom results in ultraviolet radiation. Infrared radiation will be obtained in the transition from-
The energy of the em waves is of the order of 15 keV. To which part of the spectrum does it belong?
Electromagnetic waves of wavelength ranging from $$100\overset {\circ}{A}$$ to $$400 \overset {\circ}{A}$$ comes under :
When an electron jumps from higher orbit to the second orbit in hydrogen, the radiation emitted out will be in $$(R=1.09\times 10^{7}m^{-1})$$
There are only three hydrogen atoms in a discharge tube. The analysis of spectrum shows that in all the hydrogen atoms, electrons are de-exciting from the fourth orbit. What should be the maximum number of spectral lines?
The first line of the sharp series of atomic cesium is a doublet with wavelengths $$1358.8$$ and $$1469.5\,nm$$. Find the frequency intervals (in rad/s units) between the components of the sequent lines of that series.
An atom possessing the total angular momentum $$h\sqrt{6} $$ is in the state with spin quantum number $$S = 1$$. In the corresponding vector model the angle between the spin momentum and the total angular momentum is $$ \theta = 73.2^{\circ} $$. Write the spectral symbol for the term of that state.
Write the spectral symbols for the terms of a two-electron system consisting of one p electron and one d electron.