Subjective Type

The base of a parallelogram is $$(2x + 3)$$ units and the corresponding height is $$(2x - 3)$$ units. Find the area of the parallelogram in terms of $$x$$. What will be the area of parallelogram of $$x = 30$$ units?

Solution

Given,
Base of parallelogram $$=2x+3$$ units
Height of parallelogram$$(2x-3)$$ units
Step 1: Finding the area of the parallelogram in terms of $$x$$.
Area of parallelogram $$=$$ Base $$\times$$ Height

$$=(2x+3) \times (2x-3)$$

$$=(2x)^{2} - 3^{2}$$

$$=(4x^{2} - 9)$$ sq. units

Step 2: Finding the area of the parallelogram when $$x=10$$.
Here, $$x=3$$
So, Total area $$=4\times (30)^2-9$$

$$=4\times 900-9$$

$$=3600-9$$

$$=3591$$ sq. units
$$\therefore$$ Area of parallelogram $$=(4x^{2} - 9)$$ sq. units.
Area of parallelogram $$=3591$$ sq. units when $$x=10$$

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