Single Choice

The boiling points of ethyl acetate and $${CH}_{3}OH$$, respectively are $${77}^{O}C$$ and $${65}^{o}C$$. Which of the following reactions can be shifted to the right by the distillation of the reaction mixture at about $${66}^{o}C$$. $$I. MeCOOEt+MeOH\rightarrow$$ $$II. MeCOOMe+EtOH\rightarrow$$ $$III. MeCOOMe+PhOH\rightarrow$$ $$IV. MeCOOPh+MeOH\rightarrow$$

A$$(I), (II)$$
B$$(II), (III)$$
C$$(I),(III)$$
D$$(II), (IV)$$
Correct Answer

Solution

In (II) the products are ethyl acetate (boiling point $${77}^{o}C$$) and $$MeOH$$ (boiling point $${65}^{o}C$$). Thus at $${66}^{o}C$$, $$MeOH$$ is removed due to distillation and equilibrium is shifted to R.H.S
In (IV) phenyl acetate is more reactive than methyl acetate.

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