Organic Compounds Containing Nitrogen
The correct order of reactivity towards the electrophilic substitution of the compounds aniline $$(I)$$, benzene $$(II)$$ and nitrobenzene $$(III)$$ is:
The carbylamine reaction is:
The carbylamine reaction is represented by the option (B).
Primary amines (aromatic or aliphatic) on warming with chloroform and alcoholic $$KOH$$, given carbylamine having offensive smell. This reaction is called carbylamine reaction.
The correct order of reactivity towards the electrophilic substitution of the compounds aniline $$(I)$$, benzene $$(II)$$ and nitrobenzene $$(III)$$ is:
When semicarbazide reacts with a ketone(or aldehyde) to form semicarbazone. Only one nitrogen atom of semicarbazide acts as a nucleophile and attack the carbonyl carbon of the ketone. The product of the reaction consequently is $${ R }_{ 2 }C=N-NH-CO{ NH }_{ 2\\ }$$ rather than $${ R }_{ 2 }C=NCONH-{ NH }_{ 2 }$$. What factor account for the fact that two nitrogen atoms of semicarbazide are relatively non nucleophilic?
The correct order of reactivity towards the electrophilic substitution of the compounds aniline (I) benzene (II) and nitrobenzene (III) is
Give one chemical test to distinguish between the following pairs of compounds. (i) Methylamine and dimethylamine (ii) Secondary and tertiary amines (iii) Ethylamine and aniline (iv) Aniline and benzylamine (v) Aniline and N-methylaniline.
Account for the following: (i) pKb of aniline is more than that of methylamine. (ii) Ethylamine is soluble in water whereas aniline is not. (iii) Methylamine in water reacts with ferric chloride to precipitate hydrated ferric oxide.
Primary and secondary amines react with acid chloride or acid anhydride to form:
Following reaction gives two products. $$\displaystyle { CH }_{ 3 }{ CH }_{ 2 }{ NH }_{ 2 }\xrightarrow { ({ CH }_{ 3 }CO{ ) }_{ 2 }O,\ heat }A+B$$ Write the structures of the products formed.
(A) is
Give the structures of $$A,B$$ and $$C$$ in the following reaction: $${ CH }_{ 3 }COOH\xrightarrow [ \Delta ]{ { NH }_{ 3 } } A\xrightarrow [ ]{ { Br }_{ 2 }+KOH } B\xrightarrow [ ]{ CH{ Cl }_{ 3 }+NaOH } C$$
Ethylamine reacts with acetyl chloride to form: