Single Choice

The compound that will react with $$HBr$$ most readily is:

A$$\displaystyle \left ( CH_{3} \right )_{3}COH$$
Correct Answer
B$$\displaystyle \left ( CH_{3} \right )_{2}CHOH$$
C$$\displaystyle CH_{3}CH_{2}OH$$
D$$\displaystyle C_{6}H_{5}OH$$

Solution

Reactivity order of alcohols with HBr is 3∘>2∘>1∘ alcohol.
The option (A) is a 3∘ alcohol and hence it will react most readikly with HBr.
Phenol (option D) does not react with HBr. (Ar-O) bond is not broken unless the ring is activated by the presence of electron withdrawing group (e.g., NO2) at o- and p-positions.


SIMILAR QUESTIONS

Alcohols, Phenols and Ethers

$$HBr$$ reacts fastest with:

Alcohols, Phenols and Ethers

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Alcohols, Phenols and Ethers

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Alcohols, Phenols and Ethers

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Alcohols, Phenols and Ethers

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Alcohols, Phenols and Ethers

Which of the following is responsible for iodoform reaction

Alcohols, Phenols and Ethers

t-butyl alcohol reacts less rapidly with metallic sodium than the primary alcohol. Explain why?

Alcohols, Phenols and Ethers

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Alcohols, Phenols and Ethers

State whether the following statement is True or False. Methyl alcohol gives iodoform test.

Alcohols, Phenols and Ethers

State whether the following statement is True or False. $$FeSO_4+H_2O_2$$ is called Fenton's reagent.

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