States of Matter - Gas and Liquid
The compressibility factor for $$H_{2}$$ and $$He$$ is usually:
The compressibility factor for $$CO_2$$ at 273 $$K$$ and 100 $$atm$$ pressure is 0.2005. The volume occupied by 0.2 mole of $$CO_2$$ gas at 100 $$atm$$ and 273 $$K$$ using real gas nature is $$8.89\times 10^{-x} \:litre$$. So, value of $$x$$ is.....
For real gas $$Z=\frac {PV}{nRT}$$
$$0.2005=\frac {100\times V}{0.2\times 0.082\times 273}$$
$$\therefore V=8.89\times 10^{-3} \:litre$$
so value of $$x$$ is 3.
The compressibility factor for $$H_{2}$$ and $$He$$ is usually:
If $$ Z$$ is a compressibility factor, van der Waals equation at low pressure can be written as:
The behaviour of a real gas is usually depicted by plotting compressibility factor Z versus P at a constant temperature. At high temperature and high pressure, Z is usually more than one. This fact can be explained by van der Waal's equation when:
At low pressures, the van der Waals equation is written as $$\displaystyle \left [ P+\frac{a}{V^2} \right ]V=RT$$ The compressibility factor is then equal to :
Consider the following table: Gas $$a/(k Pa dm^6 mol^{-1})$$ $$b / (dm^3 mol^{-1})$$ A 642.32 0.05196 B 155.21 0.04136 C 431.91 0.05196 D 155.21 0.4382 a and b are vander waals constant. The correct statement about the gases is:
At very high pressures, the compressibility factor of one mole of a gas is given by :
The compressibility factor for a real gas at high pressure is:
At a moderate pressure, the van der Waal's equation is written as: $$\left[P+\dfrac{a}{V^2}\right]V=RT$$ The compressibility factor is equal to:
Calculate the number of $$\alpha$$ and $$\beta$$ particles is the following change : $$U^{235}_{92}\longrightarrow \, ^{207}_{82}Pb$$
For a real gas, the compressibility factor $$Z$$ has different values at different temperature and pressures. Which of the following is not correct under the given condition?