Single Choice

The correct order of stability for the given alkoxides is :

A$$(C) > (B) > (A)$$
Correct Answer
B$$(C) > (A) > (B)$$
C$$(B) > (C) > (A)$$
D$$(B) > (A) > (C)$$

Solution

[Ref. image 1]
Here, in this case, we have to determine the stability of alkoxides.

Here $$C$$ is more stable because in this case -ve charge on $$O$$ is in conjugation with a double bond and $$NO_2$$. So there is an extra double bond in conjugation as,
[Ref. image 2]

Then comes $$B$$ as in case of $$B$$, -ve charge on oxygen is in conjugation with a double bond and not with $$NO_2$$
[Ref. image 3]

In case of $$A$$, there is no double bond so, no conjugation possible. So, least stable.

So, stability order is $$C > B > A$$

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