Single Choice

The efficiency of fuel cell is given by the expression, $$\eta $$ is:

A$$\eta =-\cfrac { nF{ E }_{ cell } }{ \Delta H } \times 100$$
Correct Answer
B$$\eta =-\cfrac { nF{ E }_{ cell } }{ \Delta S } \times 100\quad $$
C$$\eta =-\cfrac { nF{ E }_{ cell } }{ \Delta A } \times 100$$
DNone of the above

Solution

Efficiency of fuel cell is $$ \displaystyle \eta =-\cfrac { nF{ E }_{ cell } }{ \Delta H }

\times 100$$.

The thermodynamic efficiency of the fuel cell is the ratio of the electrical free energy to the enthalpy change of the reaction.

$$ \displaystyle \eta = \cfrac { \Delta G }{ \Delta H }

\times 100$$

Also, $$ \displaystyle \Delta G =- { nF{ E }_{ cell } } $$

Hence, option A is correct.

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