Single Choice

The electrolytic decomposition of dilute sulphuric acid with platinum electrode, cathodic reaction is :

AReduction of $$H^+$$
Correct Answer
BOxidation of $$SO_{4}^{2-} $$
CReduction $$SO_{3}^{2-} $$
DOxidation of $$H_2O$$

Solution

Pt electrodes are inert. They won't play any part in the reaction at either electrodes. Dil-$$H_{2}SO_{4}$$ implies that both $$H_{2}SO_{4}$$ and $$H_{2}O$$ are involved in the electrolyte.$$H^{+}$$ from $$H_{2}SO_{4}$$ and $$H^{+}$$ from $$H_{2}O$$ will be attracted to the cathode.

$$2H^{+} + 2e^{-} \rightarrow H_{2}$$

This is a gain of electrons and so, the reaction is reduction.

Hence , option A is correct .

SIMILAR QUESTIONS

Electrochemistry

On electrolysis of dil. sulphuric acid using Platinum (Pt) electrode, the product obtained at anode will be

Electrochemistry

During electrolysis of an aqueous of sulphuric acid between platinum electrodes, two types of anions migrate towards the anode but only one of them is discharged. Name the two anions.

Electrochemistry

During electrolysis of an aqueous of sulphuric acid between platinum electrodes, two types of anions migrate towards the anode but only one of them is discharged. Name the main product of the discharge of anion at the anode and write the anode reaction.

Electrochemistry

During electrolysis of an aqueous of sulphuric acid between platinum electrodes, two types of anions migrate towards the anode but only one of them is discharged. Name the product at the cathode and write the reaction.

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Define and give an example: Electrolysis.

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During electrolysis of an aqueous of sulphuric acid between platinum electrodes, two types of anions migrate towards the anode but only one of them is discharged. Why this electrolysis is considered as an example of catalysis?

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State the electrode reaction at the anode during electrolysis of very dilute sulphuric acid.

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Name the gas released at cathode when acidulated water is electrolyzed.

Electrochemistry

When an aqueous solution of $$H_{2}SO_{4}$$ is electrolysed, the product at anode is:

Electrochemistry

During electrolysis of $$H_2SO_4 (aq)$$ with high charge density, $$H_2S_2O_8$$ formed as by product. In such electrolysis $$22.4\,L \, H_2 (g)$$ and $$8.4\,L \, O_2(g) $$ liberated at $$1$$ atm and $$273\,K$$ at electrode. The moles of $$H_2S_2O_8$$ formed is:

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