Subjective Type

The frequency of vibration of a string depends on teh length L between the nodes, the tension F in the string and its mass per unit length m. Guess the expression for its frequency from dimensional analysis.

Solution

Frequency $$f=KL^aF^bM^cM=$$Mass/unit length, $$L=$$length, $$F=$$tension(forcE)
Dimension of $$f=[T^{-1}]$$
Dimension of right side,
$$L^a=[L^a], F^b=[MLT^{-2}]^b, M^c=[ML^{-1}]^c$$
$$\therefore [T^{-1}]=K[L]^3[MLT^{-2}]^b, M^c=[ML^{-1}]^c$$
$$M^0L^0T^{-1}=KM^{b+c}L^{a+b+c}T^{-2b}$$
Equating the dimensions of both sides,
$$\therefore b+c=0$$ .......$$(1)$$
$$-c+a+b=0$$ .......$$(2)$$
$$-2b=-1$$ ........$$(3)$$
Solving the equations we get,
$$a=-1, b=1/2$$ and $$c=-1/2$$
$$\therefore$$ So, frequency $$f=KL^{-1}F^{1/2}M^{-1/2}=\dfrac{K}{L}F^{1/2}M^{-1/2}=\dfrac{K}{L}=\sqrt{\dfrac{F}{M}}$$.


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