Units and Dimensions
Find the dimension of linear momentum.
The frequency of vibration of a string depends on teh length L between the nodes, the tension F in the string and its mass per unit length m. Guess the expression for its frequency from dimensional analysis.
Frequency $$f=KL^aF^bM^cM=$$Mass/unit length, $$L=$$length, $$F=$$tension(forcE)
Dimension of $$f=[T^{-1}]$$
Dimension of right side,
$$L^a=[L^a], F^b=[MLT^{-2}]^b, M^c=[ML^{-1}]^c$$
$$\therefore [T^{-1}]=K[L]^3[MLT^{-2}]^b, M^c=[ML^{-1}]^c$$
$$M^0L^0T^{-1}=KM^{b+c}L^{a+b+c}T^{-2b}$$
Equating the dimensions of both sides,
$$\therefore b+c=0$$ .......$$(1)$$
$$-c+a+b=0$$ .......$$(2)$$
$$-2b=-1$$ ........$$(3)$$
Solving the equations we get,
$$a=-1, b=1/2$$ and $$c=-1/2$$
$$\therefore$$ So, frequency $$f=KL^{-1}F^{1/2}M^{-1/2}=\dfrac{K}{L}F^{1/2}M^{-1/2}=\dfrac{K}{L}=\sqrt{\dfrac{F}{M}}$$.
Find the dimension of linear momentum.
Find the dimensions of frequency.
Find the dimensions of pressure.
Find the dimensions of electrifc field E. The relevant equations are $$F=qE, F=qvB$$ and $$B=\dfrac{\mu_oI}{2\pi a}$$ where F is force, q is charge, v is speed, I is current, and a is diatance.
Find the dimensions of magnefic field B. The relevant equations are $$F=qE, F=qvB$$ and $$B=\dfrac{\mu_oI}{2\pi a}$$; where F is force, q is charge, v is speed, I is current, and a is distance.
Find the dimensions of magnetic permeability $$\mu_o$$. The relevant equations are $$F=qE, F=qvB$$ and $$B=\dfrac{\mu_oI}{2\pi a}$$; where F is force, q is charge, v is speed, I is current, and a is distance.
Find the dimensions of electric dipole moment p. The defining equations are $$p=q.d$$ and $$M=IA$$; where d is distance, A is area, q is charge and I is current.
Find the dimensions of magnetic dipole moment M. The defining equations are $$p=q.d$$ and $$M=IA$$; where d is distance, A is area, q is charge and I is current.
Which of the following pairs has quantities of the same dimensions ?
If $$v=$$velocity of a body $$c=$$ speed of light Then the dimensions of $$\dfrac{v}{c}$$ is: