Single Choice

The highest oxidation state shown by element with atomic number 23 is:

A5
Correct Answer
B4
C3
D6

Solution

$$Z=23$$
Vanadium $$=[Ar]4s^23d^3$$,
$$5$$ valence electrons
So, maximum oxidation state it could show is $$+5$$ by ionizing all the valence electrons.

SIMILAR QUESTIONS

d - block and f - block Elements

Compounds of which of the following transition elements do not exhibit an oxidation state of +3?

d - block and f - block Elements

Mercurous ion is represented as:

d - block and f - block Elements

The element that acts as a good catalyst for several reactions has a atomic number:

d - block and f - block Elements

The element that usually does not show variable oxidation states is :

d - block and f - block Elements

Which of the following statements about $$Na_2O_2$$ is not correct?

d - block and f - block Elements

Which one of the following exhibits the largest number of oxidation states?

d - block and f - block Elements

In context with the transition elements, which of the following statements is incorrect?

d - block and f - block Elements

Which one of the following species is stable in aqueous solution

d - block and f - block Elements

Iron exhibits +2 and +3 oxidation states. Which of the following statements about iron is incorrect?

d - block and f - block Elements

The correct statement(s) about $$\displaystyle Cr^{2+}$$ and $$\displaystyle Mn^{3+}$$ is(are): $$\displaystyle \mathrm {\left [ Atomic\ numbers\ of\ Cr = 24\ and\ Mn = 25 \right ]}$$

Contact Details