Single Choice

The intensity of electric field due to a proton, at a distance of $$0.2\ nm$$ is ?

A$$3.6\times{10}^{8}{NC}^{-1}$$
B$$3.6\times{10}^{10}{NC}^{-1}$$
Correct Answer
C$$3.6\times{10}^{12}{NC}^{-1}$$
D$$3.6\times{10}^{13}{NC}^{-1}$$

Solution


SIMILAR QUESTIONS

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An electric dipole is formed by two equal and opposite charges q with separation d. The charges have same mass m. It is kept in a uniform electric field E. If it is slightly rotated from its equilibrium orientation, then its angular frequency $$\omega$$ is :-

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