The intensity of magnetic induction field at the centre of a single turn circular coil of radius $$5\ $$cm carrying of $$0.9\ $$A current is:
Magnetic field at the center of a circular current carrying coil is,
$$\dfrac{\mu_0 i}{2R}=\dfrac{4\pi\times 10^{-7}\times 0.9}{2\times 0.05}\ T$$
$$=36\pi\times 10^{-7}\ T$$
Hence correct answer is option A.
Consider two thin identical conducting wires covered with very thin insulating material. One of the wires is bent into a loop and produces magnetic field $$B_1$$, at its centre when a current $$I$$ passes through it. The second wire is bent into a coil with three identical loops adjacent to each other produces magnetic field $$B_2$$ at the centre of the loops when current $$\dfrac{I}{3}$$ passes through it. The ratio $$B_1 : B_2$$ is :
A long wire carrying a steady current is bent into a circular loop of one turn. The magnetic filed at the centre of the loop is B. It is them bent into circular coil of n turns. The magnetic field at the centre of this cold of n turns will be.
Charge $$q$$ is uniformly spread on a thin ring of radius $$R$$. The ring rotates about its axis with a uniform frequency $$f Hz$$. The magnitude of magnetic induction at the centre of the ring is
A current passing through a circular coil of two turns produces a magnetic field B as its centre. The coil is then rewound so as to have four turns and the same current is passed through it. The magnetic field at its centre now is:
A long straight conductor is bent into shape as shown. If it carries $$1\;A$$ and its radius is R, then magnetic field B at the centre of circular coil
Find the magnetic field $$B$$ due to a semicircular wire of radius $$10.0cm$$ carrying a current of $$5.0A$$ at its centre of curvature.
A circular coil of $$200$$ turns has a radius of $$10 cm$$ and carries a current of $$2.0 A$$. Find the magnitude of the magnetic field $$\vec{B}$$ at the centre of the coil.
A helium nucleus makes a full rotation in a circle of radius $$0.8\ m$$ in two seconds. The value of the magnetic field $$B$$ at the centre of the circle will be
An equilateral triangle of side $$a$$ is formed by a piece on uniform resistance wire. Current $$I$$ is feed in one corner and feed also at the other corner. The magnetic field at the centre $$O$$ due to the current in the loop is :
A circular coil of wire consisting of $$100$$ turns, each of radius $$8.0\ cm$$ carries a current of $$0.40\ A$$. What is the magnitude of the magnetic field $$B$$ at the centre of the coil?