Mole Concept
Number of moles of solute dissolved in 1000 gm of the solvent is called:
The molality of the solution containing 15.20 g of urea (molar mass = 60) dissolved in 150 g of water is:
$$\displaystyle \text { molality } = \dfrac { \text { mass of urea } }{ \text { molar mass of urea } \times \text { mass of water in kg} }$$
$$\displaystyle \text { molality } = \dfrac { \text { 15.20 g} }{ \text { 60 g/mol} \times \text { 0.150 kg} } $$
$$\displaystyle \text { molality } = \text { 1.689 mol/kg} $$
Hence, option A is correct.
Number of moles of solute dissolved in 1000 gm of the solvent is called:
In which mode of expression, the concentration of a solution remains independent of temperature?
The density of $$1$$ M solution of $$NaCl$$ is $$1.0585\:g\:ml^{-1}$$. The molality of the solution is :
If $$20\:mL$$ of ethanol (density$$=\,0.7893\:g/mL$$) is mixed with $$40\:mL$$ water (density$$=\,0.9971\:g/mL$$) at $$25^{\circ}C$$, the final solution has density of $$0.9571\:g/mL$$. Calculate the molality of alcohol in the final solution. (as nearest integer)
What is the concentration of a solution of 2,000 grams of water in which 684 grams of sucrose, $$\displaystyle { C }_{ 12 }{ H }_{ 22 }{ O }_{ 11 }$$ is dissolved?
3.42g of a substance of molecular weight 342, is present in 250g of water. Molality of this solution is:
3 g of salt having molecular weight 30 is dissolved in 250 g of water. The molality of the solution is:
A compound H$$_2$$X with molar weight of 80g is dissolved in a solvent having density of 0.4 gml$$^{-1}$$. Assuming no change in volume upon dissolution, the molality of a 3.2 molar solution is:
The mole fraction of urea in aqueous urea containing $$900\ g$$ of water is $$0.05$$. If the density of the solution is $$1.2\ g/cm^3$$, the molarity of urea solution is ______.
An aqueous solution of urea containing 18g urea in 1500 cm$$^3$$ of the solution has a density equal to 1.052. If the molecular weight of urea is 60, the molality of the solution is: