Single Choice

The number of optically active products obtained from the complete ozonolysis of the given compound are:

A0
Correct Answer
B1
C2
D4

Solution

Products we get from ozonolysis are:
$$2CH_3-COOH+2HOOC-\underset {|}{C}H-COOH$$
$$CH_3$$
Since plane of symmetry is present in both the products. It is optically inactive.

SIMILAR QUESTIONS

Hydrocarbons

Baeyer’s reagent oxidises ethylene to :

Hydrocarbons

Two moles of formaldehyde can be obtained by the following :

Hydrocarbons

Ethylene gives epoxy ethane on oxidation with :

Hydrocarbons

In the hydroboration - oxidation reaction of propene with diborane, $$H_2O_2$$ and NaOH, the organic compound formed is:

Hydrocarbons

In the following sequence of reactions, products A, B, C, D and E are formed.Which statement is correct about the reaction (B) to (C) ?

Hydrocarbons

The compound $$X$$ on ozonolysis, followed by reduction gives two mole of acetaldehyde. The $$X$$ is:

Hydrocarbons

Acid-catalyzed hydration, oxymercuration-demercuration, and hydroboration-oxidation reaction will give the same product with :

Hydrocarbons

Consider the following reaction $$CH_2=CH_2\underset {H_2O.NaOH}{\xrightarrow {dilute KMnO_4}}HOCH_2-CH_2OH$$ Which of the following statements is correct about the procurement of two oxygen in the product?

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