Single Choice

The number of possible isomers of an octahedral complex, $$[Co(C_2O_4)_2(NH_3)_2]^-$$ is :

A$$1$$
B$$2$$
C$$3$$
Correct Answer
D$$4$$

Solution

Isomers are molecules that have the same molecular formula, but have a different arrangement of the atoms in space.
$$[Co(C_2O_4)_2(NH_3)_2]^−$$ has three possible isomers shown in figure:

SIMILAR QUESTIONS

Coordination Compounds

Which of the following complexes will show geometrical isomerism?

Coordination Compounds

The ratio of cis and trans-isomers of the complex $$[Ma_{2}bcde]^{n\pm}$$ is

Coordination Compounds

Which of the following complex compound exhibits geometrical isomerism?

Coordination Compounds

How many isomers are there for the octahedral complex $$[CoCl_{2}(en)(NH_{3})_{2}]^{+}$$?

Coordination Compounds

Which one of the following octahedral complexes will not show geometric isomerism ? (A and B are monodentate ligands)

Coordination Compounds

Theoretically, the number of geometrical isomers expected for octahedral complex, $$[Mabcdef]$$ is :

Coordination Compounds

What are facial and meridional isomers? Explain with examples.

Coordination Compounds

Find the number of facial isomers in $$Ma_3b_3$$ complex.

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