Single Choice

The Poisson's ratio of a material is 0.4. If a force is applied to a wire of this material, there is a decrease of cross-sectional area by 2%. The percentage increase in its length is :

A$$3$$%
B$$2.5$$%
Correct Answer
C$$1$$%
D$$0.5$$%

Solution

Poisson's ratio, $$0.4=\cfrac{\Delta d/d}{\Delta l/l}\Rightarrow\cfrac{\Delta l}{l}=\cfrac{\Delta d/d}{0.4}$$-------------(1)
$$A=\pi r^2=\cfrac{\pi d^2}{4}$$
Taking log both sides:
$$ \log A=\log {(\frac{\pi}{4})}+2\log {d}$$
Taking relative change both the sides:
$$ \cfrac{\Delta A}{A}=2\cfrac{\Delta d}{d}\\ \cfrac{\Delta d}{d}=\cfrac{1}{2}\cfrac{\Delta A}{A}=\dfrac{1}{2}\times 2\%=1\%$$------------------------------(1)
From equation (1) and (2), the percentage increase length can be given as:
$$ \cfrac{\Delta l}{l}=\cfrac{1\%}{0.4}=2.5\%$$
Option B is correct


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