Single Choice

The position of $$Cs^+$$ ion in $$CsCl$$ structure is:

Aat the corners of the cube and body centre of the cube
Bat the centre of each face of the cube
Cat the body centre of the cube
Correct Answer
Dat the edge centre of the cube

Solution

Cation, $$Cs^+$$ is at the body centre of the cube and all anions are at the corner of the cube.

SIMILAR QUESTIONS

Solid State

Co-ordination number of the cation is maximum in :

Solid State

The number of oppositely charged nearest neighbours to a Caesium ion in Caesium Chloride lattice are:

Solid State

$$CsCl$$ crystallises in body centred cubic lattice. If $$ a$$ is its edge length, then which of the following expressions is correct?

Solid State

CsCl has bcc structure with $$Cs^{+}$$ at the centre and $$Cl^{-}$$ ion at each corner. If $$r_{Cs^+}$$ is $$1.69 \,\mathring {A}$$ and $$r_{Cl^-}$$ is $$1.81 \,\mathring {A},$$ what is the edge length of the cube ?

Solid State

What is the co-ordination number of $$Cl^{-}$$ in $$CsCl$$ structure ?

Solid State

In a crystal of $$CsCl$$, the nearest neighbours of each $$Cs$$ ion are:

Solid State

If the length of the body diagonal for CsCl which crystallises into a cubic structure with $$Cl^-$$ ions at the corners and $$Cs^+$$ ions at the centre of the unit cells is $$7\ \mathring A$$ and the radius of the $$Cs^+$$ ion is $$1.69\ \mathring A$$. What is the radii (in $$\mathring A$$) for $$Cl^-$$ ion?

Solid State

For cesium chloride structure, the interionic distance (in terms of edge length, a) is equal to $$\displaystyle \frac{\sqrt{3a}}{2}$$.

Solid State

Cesium chloride forms a body-centered cubic lattice. Cesium and chloride ions are in contact along the body diagonal of the unit cell. The length of the side of the unit cell is $$412$$ pm and $$Cl^-$$ ion has a radius of $$181$$ pm. Calculate the radius (in pm) of $$Cs^+$$ ion.

Solid State

The $$8\,\colon\,8$$ type of packing is present in___________.

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