Single Choice

The product on monobromination of this compound is :

A
B
Correct Answer
C
D

Solution

It is electrophilic substitution, so electrophile must be attacked at o/p position due to higher electron density at these positions. Ring $$(A)$$ is activated by $$+R$$ effect of $$(-NH)$$ group, while ring $$(B)$$ has EW $$\left( -\overset { O\\ \parallel }{ C } - \right) $$ group.
So, SE reaction will take place at p-position of ring $$(A)$$ since o-position is blocked.

SIMILAR QUESTIONS

Haloalkanes and Haloarenes

In Friedel craft alkylation of benzene with methyl chloride, the catalyst used is:

Haloalkanes and Haloarenes

The reaction of toluene with chlorine in the presence of ferric chloride gives predominantly:

Haloalkanes and Haloarenes

Chlorobenzene is formed by reaction of chlorine with benzene in the presence of $$A1C1_3$$.Which of the following species attacks the benzene ring in this reaction?

Haloalkanes and Haloarenes

Chloroform on treatment with phenol in presence of caustic alkali forms salicylaldehyde. This reaction is known as:

Haloalkanes and Haloarenes

Benzene reacts with $$CH_{3}Cl$$ in the presence of anhydrous $$AlCl_{3}$$ to form:

Haloalkanes and Haloarenes

The compound $$C_{7}H_{8}$$ undergoes the following reactions: $$C_{7}H_{8}\xrightarrow {3Cl_{2}/\triangle}A \xrightarrow {Br_{2}/ Fe} B \xrightarrow {Zn/HCl}C$$. The product $$C$$ is:

Haloalkanes and Haloarenes

Among the following, the reaction that proceeds through an electrophilic substitution is:

Haloalkanes and Haloarenes

On commercial scale, phenol is obtained from chlorobenzene. The chlorobenzene needed for the purpose is prepared by:

Haloalkanes and Haloarenes

In which of the following reactions, the correct major product formed?

Haloalkanes and Haloarenes

When phenol is treated with excess bromine water, it gives:

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