The range of a projectile fired at an angle of $$15^{o}$$ is $$50\ m$$. If it is fired with the same speed at an angle of $$45^{o}$$, its range will be
Given:
In the first case,Range $$=50$$ m, at an angle $$15^\circ$$
as we know that Range = $$\dfrac{u^{2} \sin 2θ}{g}$$
$$\dfrac{u^{2}\sin (2\times15)}{g} =50$$
=>$$\dfrac{u^{2}}{g}=100$$
in the second case,Range =$$\dfrac{u^{2}\sin( 2\times45)}{g}$$
=>Range =$$\dfrac{u^{2}\sin 90}{g}$$
So, Range =$$\dfrac{u^{2}}{g}$$ = 100 m
Option D is correct
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