Single Choice

The ratio of specific charge of a proton and an $$\alpha$$-particle is:

A$$2 : 1$$
Correct Answer
B$$1 : 2$$
C$$1 : 4$$
D$$1 : 1$$

Solution

Let charge of proton be $$+e$$, then the charge of an alpha particle will be $$+2e$$. Similarly, let the mass of proton be $$m$$, then mass of alpha particle will be $$4m$$.

Now, specific charge = charge/mass of the substance.

For proton, specific charge $$= e/m$$

For alpha particle, specific charge = 2e/4m

Therefore there ratio is $$: \dfrac{(e/m)}{ (2e/4m)} = 2:1$$

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