Single Choice

The slope of graph drawn between stopping potential and frequency of incident light for a given surface will be:-

Ah
Bh/e
Correct Answer
Ceh
De

Solution

$$eV_{o}= h V [V_{o}= Stooping\ potential, V= frequency ]$$
$$\dfrac{V_{o}}{V}= \dfrac{h}{e} = $$ side

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