Single Choice

The stability constants of the complexes formed by a metal ion $$(M^{2+})$$ with $$NH_3,CN^-,H_2O$$ and $$en$$ are of the order $$10^{11},10^{27},10^{15}$$ and $$10^8$$ respectively. Then:

A$$en$$ is the strongest ligand
B$$CN^-$$ is the strongest ligand
Correct Answer
Cthese values cannot predict the strength of the ligend
Dall ligands are equally strong

Solution

The stability constant for the complex $$[M(CN)_6]^{4-}$$ is maximum ($$10^{27}$$). Hence, cyanide ion is the strongest ligand. For monodentate ligands, higher is the value of stability constant, greater is the ligand strength.

SIMILAR QUESTIONS

Coordination Compounds

Which of the following is diamagnetic?

Coordination Compounds

Explain the following: $$Co^{2+}$$ is easily oxidised to $$Co^{3+}$$ in the presence of a strong ligand.

Coordination Compounds

A $$[Cr(H_2O)_6]^{3-}$$ complex typically absorbs at around $$574 \ nm$$. It is allowed to react with ammonia to form a new complex $$[Cr(NH_3)_6]^{3+}$$ that should have absorption at :

Coordination Compounds

What is the correct electronic configuration of the central atom is $$K_4(Fe(CN)_6]$$ on crystal field theory?

Coordination Compounds

$$[Fe(H_2O)_5NO]^{2+}$$ is a complex formed during the brown ring test for $$NO^-_3$$ ion. In this complex :

Coordination Compounds

$$\Delta_o$$ increases in the order of $$[CrCl_6]^{3-} < [Cr(CN)_6]^{3-} < [Cr(C_2O_4)_3]^{3-}$$.

Coordination Compounds

The value of the 'spin only' magnetic moment for one of the following configurations is $$2.84$$ BM. The correct one is?

Coordination Compounds

Among the ligands $$NH_3, en, CN^-$$ and $$CO$$, the correct order of their increasing field strength is?

Coordination Compounds

Given complexes are low spin complexes, [V(CN)6]4− [Cr(NH3)6]2+ [Ru(NH3)6]3+ [Fe(CN)6]4− then order of magnetic moment (μ) for V2+,Fe2+,Cr+3,Ru3+ is:

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