Single Choice

The volume of a closed reaction vessel in which the equilibrium $$2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g)$$ sets is halved now:

Athe rates of forward and backward reactions will remain the same .
Bthe equilibrium will not shift
Cthe equilibrium will shift to the right
Dthe rate of forward reaction will become double that of reverse reaction and the equilibrium will shift to the right
Correct Answer

Solution

$$2 SO_2(g) + O_2(g)\rightleftharpoons 2SO_3(g)$$ In this reaction three moles (or volumes`) of reactants are converted into two moles (or volumes) of products i.e. there is a decrease in volume and so if the volume of the reaction vessel is halved the equilibrium will be shifted to the right i.e. more product will be formed and the rate of forward reaction will increase i.e.double that of reverse reaction.


SIMILAR QUESTIONS

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