Single Choice

The weight of solute present in 200 mL of 0.1 M $$H_2SO_4$$ is:

A$$2.45 \ g$$
B$$4.9 \ g$$
C$$1.96 \ g$$
Correct Answer
D$$3.92\ g$$

Solution

Molarity is a measure of the concentration of a solute in a solution or of any chemical species, in terms of the amount of a substance in a given volume.
Molar concentration or molarity is most commonly expressed in units of moles of solute per litre of solution. it is represented by lowercase c:
$$c=\dfrac { n }{ V } $$
where,
$$n$$= no. of moles of solute.
$$V$$= volume of solution in liters.

Calculation:
Let the weight of solute be $$x$$ g.
Number of moles required be $$\dfrac{x}{98.07}$$
Molarity $$c=0.1\ M$$
The volume of solution in litres is $$V=\dfrac{200}{1000}=0.2$$ litres
Molarity of solution can be calculated as $$c=\dfrac { \dfrac { x }{ 98.07 } }{ 0.2 } =0.1\\ \Longrightarrow x=98.07\times 0.1\times 0.2\\ \Longrightarrow x=1.961$$ g
Weight of sulphuric acid is $$1.96$$ g.

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