If $$R=\left\{\left(x,y\right):y=2x\right\}$$ is a relation in $$A=\left\{1,2,3,4,6,7,8\right\}$$ then write all the elements of $$R$$

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Single Choice
Three concurrent forces of the same magnitude are in equillibrium. What is the angle between the force? Also name the triangle formed by the force as sides
Solution

The concurrent forces always passing through a common point.
According to Lami's theorem , $$\dfrac{C}{\sin a}=\dfrac{B}{\sin b}=\dfrac{A}{\sin c}$$
As the magnitude of forces are same so: $$A=B=C$$
Thus, $$a=b=c$$
Also, $$a+b+c=360^o$$ or $$a=b=c=360/3=120^o$$
As all forces same magnitude and same angle between them so it will make equilateral triangle.
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