Subjective Type

Two simple pendulums A and B have equal lengths, but their bobs weigh 50 gf and 100 gf respectively. What would be the ratio of their time periods? Give reason for your answer.

Solution

$$T = 2 \pi \sqrt{\dfrac{l}{g}}$$
Time period does not depend on the weight of the bob.
So, the ratio of time period will be equal to 1.

SIMILAR QUESTIONS

Measurement and Errors

The length of a simple pendulum is made one-fourth. Its time period becomes:

Measurement and Errors

Define the terms: (i) oscillation, (ii) amplitude (iii) frequency (iv) time period as related to a simple pendulum

Measurement and Errors

Name two factors on which the time period of a simple pendulum depends. Write the relation for the time period in terms of the above named factors.

Measurement and Errors

Name two factors on which the time period of a simple pendulum depends. Write the relation for the time period in terms of the above named factors.

Measurement and Errors

How does the time period (T) of a simple pendulum depend on its length(I)? Draw a graph showing the variation of $$T^2$$ with 1. How will you use this graph to determine the value of g (acceleration due to gravity)?

Measurement and Errors

A seconds' pendulum is taken to a place where acceleration due to gravity falls to one-forth. How is the time period of the pendulum affected, if at all? Give reason. What will be its new time period?

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