Organic Compounds Containing Nitrogen
Urea reacts with water to form $$A$$ which will decompose to form $$B$$. $$B$$ when passed through $$Cu^{2+} (aq)$$, deep blue colour solution $$C$$ is formed. What is the formula of $$C$$ from the following?
What happens when? (i) Urea is heated with acetoacetic ester, (ii) Urea is heated with succinic acid, (iii)Urea is treated with sodium hypobromide in alkaline medium (iv) Urea is treated with acetyl chloride
(ii) $$ NH\_ 2-\overset { \overset { O }{ \parallel } }{ C } - NH_2+NaOBr + 2NaOH \rightarrow NH_2 -NH_2+NaBr+Na_2CO_3+H_2O NH_2-NH_2+2NaOBr \rightarrow N_2 + 2NaBr + 2H_2O $$
(iv) $$ NH_ 2-\overset { \overset { O }{ parallel } }{ C } -NH_2 + CH_3 -\overset { \overset { O }{ \parallel } }{ C } -CI \rightarrow NH_2--\overset { \overset { O }{ parallel } }{ C } -NH-\overset { \overset { O }{ \parallel } }{ C } - CH_3 + HCI $$
Urea reacts with water to form $$A$$ which will decompose to form $$B$$. $$B$$ when passed through $$Cu^{2+} (aq)$$, deep blue colour solution $$C$$ is formed. What is the formula of $$C$$ from the following?
Urea on slow heating gives
An aqueous solution of urea :
A concentrated solution of urea gives a white precipitate with:
Urea is a
Urea reacts with hydrazine to give.
Urea reacts with malonic ester to give:
Urea can be distinguished from acetamide using
Urea on treatment with sodium hypobromite gives:
Urea on hydrolysis gives: