Single Choice

What is` the EAN of $${ \left[ Al{ \left( { C }_{ 4 }{ O }_{ 4 } \right) }_{ 3 } \right] }^{ 3- }$$ ?

A$$28$$
B$$22$$
Correct Answer
C$$16$$
D$$10$$

Solution

Effective atomic number $$EAN = $$ Atomic number $$-$$ oxidation number $$+2\times$$ coordination number
For $$ { \left[ Al{ \left( { C }_{ 2 }{ O }_{ 4 } \right) }_{ 3 } \right] }^{ 3- }$$
$$Z=13$$
$$ON=3$$
$$CN=6$$
$$\therefore EAN=13-3+2\times 6=22$$

SIMILAR QUESTIONS

Coordination Compounds

The effective atomic number of Cr(atomic number$$=24$$) in $$[Cr(NH_3)_6]Cl_3$$ is?

Coordination Compounds

Which of following coordinate complexes is an exception to EAN rule ? (Given Atomic Number: $$Pt = 78,\ Fe = 26,\ Zn = 30,\ Cu = 29$$)

Coordination Compounds

If EAN of central metal cation M2+ in a non-chelating complex is 36 and atomic no. of metal M is 26, then the number of monodentate ligand in this complex are

Coordination Compounds

Which of the following is an oxidizing agent?

Coordination Compounds

Which of the following pair to $$EAN$$ of central metal atom is not same?

Coordination Compounds

Choose the correct option regarding the following complex compound which follows $$(F)$$ and does not follow $$(NF)$$ the Sidgwick EAN rule: (I) $$[(Ph_{3}P)_{3}PdCl_{2}PdCl_{2}]$$ (II) $$[NiBrCl(en)]$$ (III) $$Na_{4}[Fe(CN)_{5}NOS]$$ (IV) $$Cr(CO)_{3}(NO)_{2}$$.

Coordination Compounds

Which of the following compound has/have effective atomic number equal to the atomic number of a noble gas?

Coordination Compounds

$$M(CO)_{x} (NO)_{y} \underset {-CO}{\xrightarrow {+NO}}M(NO)_{z}$$ Where $$EAN$$ of metal $$(M)$$ in both product and reactant is same and it is $$54$$. Then calculate value of $$(x + y - z)$$. (where $$x, y$$ and $$z$$ are natural numbers and $$M$$ belong to $$6^{th}$$ group according to long form of periodic table).

Coordination Compounds

Pick out the complex compound in which the central metal atom obeys EAN rule strictly :

Coordination Compounds

In $$[Ni{ \left( { NH }_{ 3 } \right) }_{ 4 }]{ SO }_{ 4 }$$, the E.A.N. of Ni is

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