Subjective Type

What is the ground-state electronic configuration of a neutral atom of neon?

Solution

The electronic configuration of an element is written with the help of Afbau's principle, which states that the lower energy states are first filled completely, then the higher energy states start to get filled.

Neon has a total of $$10$$ electrons. We know that the $$1s$$-orbital can hold up to a maximum of $$2$$ electrons. We continue this path until we reach a total of $$10$$ electrons. The $$s$$-orbitals in a shell are filled first and then the $$p$$-orbitals are filled according to the rule of $$2n^2$$ number of electrons in a particular shell. The $$p$$-orbital can hold a maximum of $$6$$ electrons.

We find the configuration to be $$ 1s^{2}2s^{2}2p^{6}$$, which we know is correct because if we add up the superscripts, we'll get the total number of electrons, i.e., $$10$$.

Therefore, the ground-state electronic configuration of a neutral atom of neon is $$1s^22s^22p^6$$ or $$[He]2s^{2}2p^{6}$$ as $$He$$ has two electrons only.

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