Physical World
Formic acid and formaldehyde can be distinguished by treating with:
When sodium formate is heated with soda lime, it forms:
When sodium acetate is treated with soda lime, decarboxylation takes place and $$CO_2$$ is eliminated from the sodium acetate . The chemical reaction is as follows :
$$HCOONa + NaOH \rightarrow H_2 + Na_2CO_3$$
hence option (A) is correct.
Formic acid and formaldehyde can be distinguished by treating with:
When sodium formate is heated at $${360}^{o}C$$, main product is:
Formic acid gives the test of:
Give one chemical test to distinguish between the following pairs of compound: Formic acid and Acetic acid.