Some Basic Concepts of Chemistry
1%(w/v) of an aqueous solution of NaOH is isomolar with:
When the volume of the solution is doubled, ______ becomes exactly half.
Molarity $$=\dfrac {No.\ of\ moles}{Volume}$$
$$M_1 = \dfrac{n}{V_1}$$
if $$V_2=2V_1$$,
$$M_2 = \dfrac {n}{V_2}$$
$$= \dfrac{n}{2V_1}$$
$$= \dfrac{M_1}{2}$$
1%(w/v) of an aqueous solution of NaOH is isomolar with:
Formula of Molarity (in ml) is .................. $$\times 100/v$$
What will be the molarity of a solution which contains $$5.85\; g$$ of $$NaCl(s)$$ per $$500$$ ml?
Stock phosphoric acid solution is $$85$$% $$H_3PO_4$$ and has a specific gravity of $$1.70$$ . Hence, molarity of $$H_3PO_4$$ solution is:
The amount of $$NaOH$$ in $$750ml$$ of $$0.2M$$ solution (Molecular weight $$=40$$) is:
An antifreeze mixture consists of $$40$$% ethylene glycol $$(C_2H_6O_2)$$ by weight in aqueous solution. If the density of this solution is $$ 1.05$$ g/mL, what is the molar concentration?
A semi molar solution is the one which contains:
Molarity of $$4\%$$ (w/v) solution of $$NaOH$$ is:
The amount of sugar $$(C_{12}H_{22}O_{11}$$) required to prepare $$2L$$ of its $$0.1 M$$ aqueous solution is:
Dissolving 120 gm of a compound of (mol. wt. 60) in 1000 g of water gave a solution of density 1.5 g/mL. The molarity of the solution is: