Single Choice

Which of the following compound cannot be prepared?

A$$\mathrm{X}\mathrm{e}\mathrm{F}_{2}$$
B$$\mathrm{X}\mathrm{e}\mathrm{F}_{3}$$
Correct Answer
C$$\mathrm{X}\mathrm{e}\mathrm{F}_{4}$$
D$$\mathrm{X}\mathrm{e}\mathrm{F}_{6}$$

Solution

Xe has a complete filled 5p configuration. As a result when it undergoes bonding with an odd number (3 or 5) of F atoms it leaves behind one unpaired electron. This causes the molecule to become unstable. As a result $$XeF_3$$ ,$$XeF_5$$ not possible.

Only even no. of fluorides can combine with Xe. Therefore $$XeF_3$$ cannot be formed, Only even bonds can be formed.

SIMILAR QUESTIONS

p - block Elements

What is the atomic number (Z) of the noble gas that reacts with fluorine?

p - block Elements

Which of the following are formed by xenon?

p - block Elements

Xenon has closed shell configuration but is known to give compounds with fluorine because:

p - block Elements

Draw the structure of the following: $$XeF_{4}$$.

p - block Elements

Who among the following first prepared a stable compound of noble gas?

p - block Elements

Xenon form compounds with fluorine under different conditions. The known fluorides are:

p - block Elements

Of the following species, one which is non-existent:

p - block Elements

Maximum number of compounds are known in the case of:

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