Haloalkanes and Haloarenes
On heating with bleaching powder, ethyl alcohol is converted into:
Which of the following reaction(s) can be used for the preparation of alkyl halides? (I) $$CH_3CH_2OH+HCl\xrightarrow {anh.ZnCl_2}$$ (II) $$CH_3CH_2OH+HCl\rightarrow$$ (III) $$(CH_3)_3COH+HCl\rightarrow$$ (IV) $$(CH_3)_2CHOH+HCl\xrightarrow {anh.ZnCl_2}$$
The reactions $$(I), (III)$$ and $$(IV)$$ only can be used for the preparation of alkyl halides.
Alkyl halide is prepared by the reaction of an alcohol with $$HCl$$ in which -$$OH$$ group is replaced with $$Cl$$.
Primary and secondary alcohols requires catalyst such as anhydrous zinc chloride.
Tertiary alcohols do not require such catalyst as they are more reactive.
On heating with bleaching powder, ethyl alcohol is converted into:
The best method to prepare neopentyl chloride is:
Write the structure of the major organic product in each of the following reactions: $$CH_3CH_2CH_2OH+SOCl_2 \rightarrow $$
In the following reaction sequence: $$\underset{(C_3H_6Cl_2)}{I} \xrightarrow {KOH(aq)} II \xrightarrow[(ii)H_2O/H^+]{(i)CH_3MgBr} III \xrightarrow{Anhy.ZnCl_2+Con.HCl} $$ give trubidity immediately
Which statement is correct?
Suggest the reagent that could be used to prepare these alkyl halides from alcohols.
The product $$(B)$$ is:
The number of possible monobromo products is (excluding stereoisomers):