Chemical Bonding
Decreasing order of size of various hybrid orbitals is :
Which of the following statement is true for $$H_2S$$ ?
The sulphur atom is $$sp3$$ hybridized and bonding takes place in ground state. Two filled orbitals $$3s^2$$ and $$3p_x^2$$ are act as lone pairs. $$H_2S\rightarrow BF_3$$ has coordinate bond, $$S$$ from $$H_2S$$ gives lone pair and $$B$$ receives it. Bond angle difference leads to form hydrogen bonds in water. so that two lone pairs of oxygen in water engaged in hydrogen bond. Formation of hyderogen bonds reduce the lone pair - bond pair repulsion. Thats why bond angle is greater in water when compare to hydrogen sulfide. In $$H_2S$$ the $$sp^3$$ hybrid orbitals are bigger than $$H_2O$$ and so the bond pair-bond pair repulsion decreases.
Decreasing order of size of various hybrid orbitals is :
Which of the following statements is the best expression for the $$sp^{3}$$ hybridization of carbon electrons?
Which of the following species has tetrahedral geometry?
Which of the following has a bond formed by overlap of $$sp^3$$ - hybrid orbitals?
In which of the following molecules, the central atom does not have $$sp^3$$ hybridization?
Few examples of the compounds formed by chemical bonding are given below. Mark the incorrect example.
Which of the following species has tetrahedral geometry?
Consider the following molecule Calculate value of $$p \div q$$, here p and q are total number of $$d\pi - p\pi$$ bonds and total number of $$sp^3$$ hybridised atoms respectively in given molecule.
The hybridization of the central atom in $$ICl_{2+}$$ is :
The Geometry of $${IF}_{7}$$ molecule: