d - block and f - block Elements
Which of the following ions will exhibit colour in aqueous solutions?
Which one of the following ions will be colourless in an aqueous solution?
$$(A)$$ $$Fe\quad [Ar]3d^64s^2$$
$$Fe^{+2}\quad [Ar]3d^6$$
$$4$$ unpaired $$e^-s\longrightarrow$$ paramagnetic.
$$(B)$$ $$Mn\quad [Ar]3d^54s^2$$
$$Mn^{+2}\quad [Ar]3d^5$$
$$5$$ unpaired $$e^-s\longrightarrow$$ paramagnetic.
$$(C)$$ $$Ti\quad [Ar]3d^24s^2$$
$$Ti^{+3}\quad [Ar]3d^1$$
$$1$$ unpaired $$e^-s\longrightarrow$$ paramagnetic.
$$(D)$$ $$Sc\quad [Ar]3d^14s^2$$
$$Sc^{+3}\quad [Ar]$$
$$0$$ unpaired $$e^-s\longrightarrow$$ dimagnetic.
Ions which are paramagnetic show colour in aqueous solution.
Which of the following ions will exhibit colour in aqueous solutions?
In which of the following pairs are both the ions coloured in aqueous solution? [At. No. : $$Sc = 21, Ti = 22, Ni = 28, Cu = 29, Co = 27$$]
The transition metal ions responsible for color in Ruby and Emerald are, respectively :
The color of $$Co{ Cl }_{ 3 }.5{ NH }_{ 3 }.{ H }_{ 2 }O$$ is:
Which of the following compound is expected to be coloured?
Which of these ions is expected to be coloured in aqueous solution? I. $${Fe}^{3+}$$ II. $${Ni}^{2+}$$ III. $${Al}^{3+}$$
Identify the oxidation states of titanium $$(Z=22)$$ and copper $$(Z=29)$$ in their colourless compounds:
Predict which of the following will be coloured in aqueous solution? $$Ti^{3+}, V^{3+}, Cu^{+}, Sc^{3+}, Mn^{2+}, Fe^{3+}$$ and $$Co^{2+}$$. Give reasons for each
Choose the correct answer from the alternative given. Amongst $$TiF_6^{2-}$$, $$CoF$$, $$Cu_2$$ $$Cl_2$$ and $$NiCl$$, which are the colourless species? (atomic number of Ti = 22, Co = 27, Cu = 29, Ni = 28)
For $$Zn^{2+}$$, $$Ni^{2+}$$, $$Cu$$, and $$Cr^{2+}$$ which of the following statements is correct?