Coordination Compounds
Among the following, the species that is both paramagnetic and coloured is :
Why a solution of $$[Ni(H_2O)_6]^{2+}$$ is green while a solution of $$[Ni(CN)_4]^{2-}$$ is colourless? (At no. of $$Ni=28$$)
In $$[Ni(H_2O)_6]^{2+}, Ni$$ is in $$+2$$ oxidation state with the configuration $$3d^8 4s^0$$, i.e., it has two unpaired electrons which do not pair in the presence of weak $$H_2O$$ ligand. The $$d-d$$ transition absorbed red light and the complementary green light is emitted.
On the other hand, in $$[Ni(CN)_4]^{2-}, Ni$$ is again in $$+2$$ oxidation state with the the electronic configuration $$3s^8$$. In the presence of strong $$CN^-$$ ligand the two unpaired electrons in the $$3d$$ orbitals pair up. As there is no unpaired electron in $$[Ni(CN)_4]^{2-}$$, therefore the complex is colourless.
Among the following, the species that is both paramagnetic and coloured is :
What is the relationship between observed color of the complex and the wavelength of light absorbed by the complex?
The colourless species is:
Which of the following compound is expected to be colourless?
Which of the following compounds is not colored yellow?
Which of the following statements is/are correct?
Which of the following is correct about $$\underset{I}{KFe^{II}[Fe(CN)_6]}$$ and $$\underset{II}{KFe^{III}[Fe(CN)_6]}$$ complex compounds?
If $$MCl_2$$ salt is white, then comment on colour of its iodide salt.
Choose incorrect statement.
Answer the following question: $$[Ni(H_2O)_6]^{2+}$$ is green whereas $$[Ni(CN)_4]^{2-}$$ is colourless. Why? (At no. of $$Ni=28$$)