Subjective Type

Why does the reaction proceed better with $$ KF $$ than with $$ NaF $$?

Solution

The standard enthalpies of formation of alkali metal chlorides become more and more negative as we move down the group, i.e. $$ \Delta_fH^o $$ of $$ KCI $$ is more negative $$ (-428 kJ mol^{-1} )$$ than that of $$ NaCI(-400 kJ mol^{-1}) $$.
Therefore, the above reaction proceeds better with $$ KF $$ than with $$ NaF$$.

SIMILAR QUESTIONS

s - block Elements (Alkali and Alkaline Earth Metals)

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