Why is molecularity applicable only for elementary reactions and order is applicable for elementary as well as complex reactions ?
A complex reaction proceeds through several elementary reactions . Number of molecules involved in each elementary reaction may be different , i.e., the molecularity of each step may be different . Therefore , discussion of molecularity of overall complex reaction is meaningless . On the other hand , order of a complex reaction is determined by the slowest step in its mechanism and is not meaningless even in the case of complex reactions .
Statement - I: For the reaction given below: The molecularity of the first step is 1 and the second step is 2. $$2O_3(g) \rightarrow 3O_2(g)$$ Step 1: $$O_3(g)\rightleftharpoons \, O_2(g) + O(g)$$ Step 2: $$O_3(g) + O \xrightarrow[]{slow} 2O_2(g)$$ Statement - II: O(g) is an intermediate. The rate of reaction is $$K[O_3]^2[O_2]^{-1}$$ and the order of the reaction is 1.
The rate of the reaction $$H_{2}(g)+Br_{2}(g)\rightarrow 2HBr(g)$$ is given by: $$r=k[H_{2}][Br_{2}]^{1/2}$$ Which among the following is correct?
Which of the following is/are true :
For a reaction; $$X + Y\rightarrow Z, rate \propto [X]$$. What is (i) molecularity and (ii) order of the reaction?
For the reaction : $$ 2NH_3 (g) \rightarrow N_2(g) + 3H_2 (g) $$ Rate $$ = k $$ Write the order and molecularity of this reaction .
What is the difference between the order of a reaction and its molecularity?
What is the difference between order of a reaction and the molecularity of a reaction?