Single Choice

A circuit contains an ammeter, a battery of $$30\ V$$ and a resistance $$40.8$$ ohm all connected in series. If the ammeter has a coil of resistance $$480$$ ohm and as shunt of $$20$$ ohm, the reading in the ammeter will be:

A$$1\ A$$
B$$0.5\ A$$
Correct Answer
C$$0.25\ A$$
D$$2\ A$$

Solution

Resistance of ammeter: $$r_{am} =\frac{ 480 \times 20}{480 + 20} =19.2$$
Current : $$i = \frac{ 30}{40.8 + 19.2} =0.5\: amp$$


SIMILAR QUESTIONS

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