Subjective Type

Find the current flowing through the resistance $$R$$ in the circuit shown in Fig. The internal resistances of the batteries are negligible.

Solution

Indicate the currents in all the branches using charge conservation as shown in the figure.

Applying loop rule, $$-\triangle \varphi = 0$$ in the loops $$1A781, 1B681$$ and $$B456B$$, respectively, we get
$$\xi_{0} = (i_{0} - i_{1}) R_{1} (1)$$
$$i_{3}R_{3} + i_{1}R_{2} - \xi_{0} = 0 (2)$$ and
$$(i_{1} - i_{3})R - \xi - i_{3} R_{3} = 0 (3)$$

Solving Eqs. (1), (2) and (3), we get the sought current
$$(i_{1} - i_{3}) = \dfrac {\xi (R_{2} + R_{3}) + \xi_{0}R_{3}}{R(R_{2} + R_{3}) + R_{2}R_{3}}$$.


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