Subjective Type

A current of $$ 5 $$ ampere is flowing through a wire for $$ 193 $$ seconds . Calculate the number of electrons flowing through the cross section of wire for $$ 193 $$ seconds .

Solution

$$ Q = I \times t = 5\,A \times 193 \,s = 965 \,C $$

$$ 96500 \,C $$ is equivalent to flow of $$ 6.022 \times 10^{23} $$ electrons .

$$ \therefore \, 965 \,C $$ will be equivalent to flow of electrons

$$ = \dfrac{6.022 \times 10^{23}}{96500} \times 965 = 6.022 \times 1021 $$.

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