A metal ring is held horizontally and bar magnet is dropped through the ring with its length along the axis of the ring. The acceleration of the falling magnet is
According to Lenz's Law, the flux through the coil will increase. And hence current will be induced in the coil such that it has the same polarity as the nearer end of bar magnet so as to oppose the fall and hence the change in flux.
Due to this, an upward force will be exerted on bar magnet due to coil.
Hence, its acceleration will be less than $$g$$.
Hence, answer is option-(B).
A metallic rod of mass per unit length $$0.5$$ kg $$m^{-1}$$ is lying horizontally on a smooth inclined plane which makes an angle of $$30^o$$ with the horizontal. The rod is not allowed to slide down by a flowing a current through it when a magnetic field of induction $$0.25$$T is acting on it in the vertical direction. The current flowing in the rod to keep it stationary is?
Lenz's law is consequence of the law of conservation of
Two identical coaxial coils $$P$$ and $$Q$$ carrying equal amount of current in the same direction are brought nearer. The current in
A metal ring is held horizontally and bar magnet is dropped through the ring with its length along the axis of the ring. The acceleration of the falling magnet is
In a discharge tube at $$0.02\ mm$$ there is a formation of
A conductor coil moving in a magnetic field produces an induced e.m.f. This is in accordance with
The direction of induced current in a coil or circuit is such that it opposes the very cause of its production. This law is given by
A copper ring is held horizontally and a bar magnet is dropped through the ring with its length along the axis of the ring. Then, the acceleration of the falling magnet (neglect air resistance) will be
Lenz's law is a consequence of the law of conservation of
The Lenz's law gives: