Single Choice

A moving coil galvanometer A has 200 turns and resistance 100 . Another meter B has 100 turns and resistance 40 . All the other quantities are same in both the cases. The current sensistivity of

AB is double as that of A
Correct Answer
BA is 2.5 times of B
CA is 5 times of B
DB is 5 times of A.

Solution

for moving coil galvanometer
$$I=(\dfrac{C}{NBA})\phi $$
$$(\dfrac{\phi }{I})=(\dfrac{NBA}{C})$$
current sensitivity $$(\dfrac{\phi }{I})=(\dfrac{NBA}{C}) $$
$$\dfrac{current sensitivity of A}{current sensitivity of B}=\dfrac{N_{1}}{N_{2}}$$
=$$\dfrac{200}{100}$$
=2:1

SIMILAR QUESTIONS

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