Single Choice

A wire of length $$L$$ is made in the form of a coil in a moving coil galvanometer. To have maximum sensitiveness the shape of the coil is

Acircular
Correct Answer
Belliptical
Crectangular
Dsquare

Solution

For a fixed given length of a wire area is maximum when it is bent in a circular shape.
Sensitivity is dependent on area of the coil. So, more area, more sensitivity of galvanometer.

SIMILAR QUESTIONS

Magnetism

Sensitivity of moving coil galvanometer is '$$s$$'. If a shunt of $$\left (\dfrac {1}{8}\right )^{th}$$ of the resistance of galvanometer is connected to moving coil galvanometer, its sensitivity becomes:

Magnetism

Sensitivity of a moving coil galvanometer can be increased by _____________. Fill in the blank.

Magnetism

Two moving coil metres $$M_1$$ and $$M_2$$ have the following particular $$R_1$$ = 10 $$\Omega$$;$$N_1$$= 30; $$A_1$$= 3.6 x $$10^{-3} m^2$$; $$B_1$$= 0.25 T; $$R_2$$ = 14$$\Omega$$; $$N_2$$= 42; $$A_2$$= 1.8 x $$10^{-3}m^2$$; $$B_2$$= 0.50 T. The spring constants are identical for the two metres. What is the ratio of current sensitivity and voltage sensitivity of $$M_2$$ to $$M_1$$?

Magnetism

The coil of a galvanometer consists of 100 turns and effective area $$1cm^{2}$$ . The restoring couple is $$10^{-8} N -m/ rad$$ . The magnetic field between the pole pieces is 5 Tesla. The current sensitivity of the galvanometer will be:

Magnetism

A moving coil galvanometer has 48 turns and area of coil is $$\displaystyle 4\times { 10 }^{ -2 }{ m }^{ 2 }$$. If the magnetic field is 0.2T, then to increase the current sensitivity by 25% without changing area (A) and field (B) the number of turns should become :

Magnetism

The sensitiveness of a moving coil galvanometer can be increased by decreasing

Magnetism

A moving coil galvanometer A has 200 turns and resistance 100 . Another meter B has 100 turns and resistance 40 . All the other quantities are same in both the cases. The current sensistivity of

Magnetism

Define the current sensitivity of galvanometer.Write its SI unit.

Magnetism

Maximum current that can pass through galvanometer is $$0.002A$$ and resistance of galvonameter is $$R_g = 50\Omega$$. find out shunt resistance to convert in into ammeter of range $$0.5 A$$.

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