Single Choice

Among the compounds $$A$$ and $$B$$ with molecular formula $${C}_{9}{H}_{18}{O}_{3}$$, $$A$$ is having higher boiling point the $$B$$. The possible structures of $$A$$ and $$B$$ are :

A
B
Correct Answer
C
D

Solution

Given molecular formula is $$C_9H_{18}O_3$$

Also, $$A$$ has higher boiling point than $$B$$.

So, for the given molecular formula we can write $$2$$ functional groups namely alcohol and ether.

And if we compared alcohol and ether in terms of their boiling point, ether has a very low boiling point than alcohols.

It is because in ethers there is no $$O-H$$ bond so it can form hydrogen bonding that is why it does not form hydrogen bonding.

But in case of alcohol, we have $$O-H$$ bond so it can form hydrogen bonding, that is why more amount of energy required to break the bonds so, more boiling point.

So, $$A$$ is alcohol and $$B$$ is ether.

Hence, option B is correct.

SIMILAR QUESTIONS

Chemical Bonding

Intramolecular hydrogen bond is not present in:

Chemical Bonding

The correct order of volalitity is:

Chemical Bonding

Draw the structure of enol form of $$\displaystyle CH_3COCH_2COCH_3$$ with intramolecular hydrogen bonding.

Chemical Bonding

The intramolecular hydrogen bonding in compound leads to:

Chemical Bonding

Out of o-nitrophenol and p-nitrophenol which has higher boiling point and why ?

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The boiling and melting points of water are abnormally higher than those of other hybrides of group 16 of the periodic table. Give reasons.

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Which concept best explains that o-nitrophenol is more volatile than p-nitrophenol?

Chemical Bonding

Which of the following compound can form hydrogen bonds?

Chemical Bonding

Intramolecular hydrogen bond is present in:

Chemical Bonding

Out of the two compounds shown above, the vapour pressure of B at a particular temperature is expected to be :

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