Chemical Bonding
Intramolecular hydrogen bond is not present in:
Out of the two compounds shown above, the vapour pressure of B at a particular temperature is expected to be :
Because of intramolecular hydrogen bonding in (B), i.e., ortho nitrophenol, the vapour pressure of ortho nitrophenol is expected to be higher than $$para \,nitrophenol.$$
Therefore, the correct option is A.
Intramolecular hydrogen bond is not present in:
The correct order of volalitity is:
Draw the structure of enol form of $$\displaystyle CH_3COCH_2COCH_3$$ with intramolecular hydrogen bonding.
Among the compounds $$A$$ and $$B$$ with molecular formula $${C}_{9}{H}_{18}{O}_{3}$$, $$A$$ is having higher boiling point the $$B$$. The possible structures of $$A$$ and $$B$$ are :
The intramolecular hydrogen bonding in compound leads to:
Out of o-nitrophenol and p-nitrophenol which has higher boiling point and why ?
The boiling and melting points of water are abnormally higher than those of other hybrides of group 16 of the periodic table. Give reasons.
Which concept best explains that o-nitrophenol is more volatile than p-nitrophenol?
Which of the following compound can form hydrogen bonds?
Intramolecular hydrogen bond is present in: