An acidic compound $$(A)$$. $$({C}_{4}{H}_{8}O)$$ loses its optical activity on strong heating yielding $$(B)$$ $$({C}_{4}{H}_{6}{O}_{2})$$ which reacts readily with $$KMn{O}_{4}$$. $$(B)$$ forms a derivative $$(C)$$ with $$SO{Cl}_{2}$$ which on reaction with $${({CH}_{3})}_{2}NH$$ gives $$(D)$$. The compound $$(A)$$ on oxidation with dilute chromic acid gives an unstable compound $$(E)$$ which decaboxylates readily to give $$(F)$$ ($${C}_{3}{H}_{6}O$$). The compound $$(F)$$ gives a hydrocarbon $$(G)$$ on treatment with amalgamated $$Zn$$ and $$HCl$$. Give the structures of $$(A)$$ to $$(G)$$ with proper reasoning.
answer is given(i) $$[A]\Rightarrow {1}^{o}$$ unsaturation on heating loses $$(-{H}_{2}O)$$ (Hydroxy acid) due to (given) group
(ii) Thirrd oxygen atom due of $$(-OH)$$ group
(iii) $$A\Rightarrow $$ Optically active, So (given)
(iv) Since (A) on heating loses $${H}_{2}O$$ thus $$(A)$$ is $$\beta$$ hydroxy not $$\alpha$$-hydroxy, because only $$\beta$$- Hydroxy loses $${H}_{2}O$$ on heating
$$CH_3-\underset{CH_3}{\underset{|}{\overset{CH_3\!\!\!\!\!\!}{\overset{|}{C}}}-}CH_2-\overset{CH_3}{\overset{|}{C}H}-CH_3$$ $$\xrightarrow{Br_2/hu}$$ For the given reaction how many products are optically active (all isomers) :
Which one of the following compounds is not optically active?
The complex / complex ion, which shows optical activity is :
An optically active alcohol $$A(C_{6}H_{10}O)$$ absorbs $$2mol$$ of hydrogen per mole of $$A$$ upon catalytic hydrogenation and gives a product $$B$$. The compound $$B$$ is resistent to oxidation by $$CrO_{3}$$ and does not show any optical activity. Deduce the structures of $$A$$ and $$B$$.
An optically active compound:
Give the stereochemical products of the following.
Which statement is correct about the above reaction?
If both compounds (A) and (B) are optically active,the possible structures of (B) are
The compounds are optically inactive because
Compound $$(E)$$ is